描述：nums1 中数字 x 的「下一个更大元素」是指 x 在 nums2 中对应位置右侧的第一个比 x 大的元素。给你两个没有重复元素的数组 nums1 和 nums2，其中 nums1 是 nums2 的子集。对于每个 nums1[i]，找出其在 nums2 中的下一个更大元素；若不存在，返回 -1。
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And that’s the beauty of it! The process may seem complicated, but it’s done in minutes with modern technology. And because technology is advancing rapidly, I expect things to move even more quickly than ever.
To withdraw cash, a user inserted a magnetic card that contained an account
would end up talking to a teller who simply keyed the transaction into a 3604,